Question

The change in the momentum of an object (Δ p) is given by the force, F, acting on the object multiplied by the time interval that the force was acting: Δ p = F Δt .

If the force (in newtons) acting on a particular object is given by F(t)=cost , what’s the total change in momentum of the object from time t = 5 until t = 7 seconds?

Answer 1

0.402 newton•sec
0.708 newton•sec
0.909 newton•sec
1.416 newton•sec
1.616 newton•sec

Answer 2

0.909 newton sec

Answer 3

How did you solve it?

Answer 4

@TheSmartOne

Answer 5

I don't know calculus... ._.

But maybe this can help you :)
https://answers.yahoo.com/question/index?qid=20120426232252AAW7OZN
http://mathhelpforum.com/calculus/226439-momentum-question.html

Answer 6

you can use the integral

Answer 7

The integral of?

Answer 8

$$
\Large{

\Delta p = F\Delta t\\ \therefore\\
Total~ Momentum = \sum \Delta p = \sum F \Delta t
\\ \therefore \\
\int dp = \int F(t) dt = \int_{5}^{7} \cos t dt


}
$$

Answer 9

\[\Delta p = \sin(7) - \sin(5)\]

Answer 10

correct?

Answer 11

correct

Answer 12

That equals 0.0347, and that's not one of my answers.

Answer 13

you are using degree mode

Answer 14

not radian mode, the question is in radians

Answer 15

Well that explains a lot. I got 1.616.

Answer 16

Thank you!

Answer 17

@perl

Answer 18

your welcome