Using a fair coin and a fair six-sided number cube, what is the probability of tossing tails and rolling a multiple of 3?
Does this have options?
no
okay, so does it want two separate ratios, one for the coin and one for the cube?
Okay. So we need to identify the sides for each one: Let's start with the coin. The coin has two sides, meaning that it would have a 1/2 chance of landing on tails. Now the cube. First we identify how many sides are on it. We know that there are 6 sides on the cube. Next, we find our multiples of 3. On this cube there are only two possible multiples of 3: 3 and 6. If there are six sides, then it would be a 2 / 6 of a chance of landing on either of those two numbers. 2/6 simplifed is 1 / 3. So, your answer is there is a 1:2 chance of landing on tails, and a 1:3 chance of landing on a multiple of 3.
@iGreen , am I correct in my explanation?
Find the multiples of 3..
1-6 3, 6 So the probability is 2/6 or 1/3. Now find the probability of tossing a tails. 1 tail out of 2 possibilities = 1/2 So multiply 1/2 * 1/3 and you got your answer.
@Zyi6 Yep, you got it.
1/3×1/2
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