Tristan says that solutions to radical equations are extraneous. Hadley says that solutions to radical equations are non-extraneous. Find an equation where Tristan is correct and a second equation where Hadley is correct. Using complete sentences, explain each step when solving to justify your examples.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Does anyone know what extraneous is?
OpenStudy (anonymous):
An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.
OpenStudy (anonymous):
Does anyone know what extraneous is?
OpenStudy (anonymous):
@Squickers I just told you what it is
OpenStudy (anonymous):
oh sorry didn't see that
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
haha it is okay :)
OpenStudy (anonymous):
welcome to os :D
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
do you need anymore help???
OpenStudy (anonymous):
nah I figures it out
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
\[\sqrt{x-2}=3\] for tristan
OpenStudy (anonymous):
\[\sqrt{x-2}=3\] for Hadley
OpenStudy (anonymous):
for tristan when you solve for x it gives you 11
OpenStudy (anonymous):
then if replace 11 for x and simplify it gives 3=-3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
meaning its extraneous
OpenStudy (anonymous):
If you do the same thing for hadley it gives you 11 again
OpenStudy (anonymous):
but when you replace x with 11 and simplify it gives you 3=3, not extraneous