Question

derivate
y=x(2x+1)^3

Answer 1

looks like i see a product, a power, and a chain rule ....

Answer 2

yes, I used the chain rule

Answer 3

did you use the other rules as well?

lets see what youve done

Answer 4

I have this( X). 6(2x+1)+ (2x+1)^3.(1)

Answer 5

y=x(2x+1)^3

D[y] = D[x (2x+1)^3]
product


D[y] = D[x] (2x+1)^3 + x D[(2x+1)^3]
power/chain



D[y] = D[x] (2x+1)^3 + x 3(2x+1)^2 D[2x+1]

Answer 6

The answer is DY= (2x+1)^2 (8x+1) But i dont know (8x+1)

Answer 7

you understand how i got this far?

D[y] = D[x] (2x+1)^3 + x 3(2x+1)^2 D[2x+1]

Answer 8

D[y] = D[x] (2x+1)^3 + x 3(2x+1)^2 D[2x+1]


D[y] = y'
D[x] = 1


y' = (2x+1)^3 + x 3(2x+1)^2 D[2x+1]
^^^^^^ just a simple derivative

y' = (2x+1)^3 + x 3(2x+1)^2 (2)

y' = (2x+1)^3 + 6x(2x+1)^2

we can factor out (2x+1)^2 ... this is just algebra


y' = (2x+1)^2 ( 2x +1 + 6x)

etc ...

Answer 9

Thanks

Answer 10

yep