Coordinate Geometry
The number of points, having both co-ordinates as integers , that lie in the interior of the triangle with vertices \(\large \color{black }{\begin{align} (0,0),(0,41)\quad and \quad (41,0)\hspace{.33em}\\~\\ \end{align}}\) is
\(\large \color{black }{\begin{align} &a.)\quad 820\hspace{.33em}\\~\\ &b.)\quad 780\hspace{.33em}\\~\\ &c.)\quad 901\hspace{.33em}\\~\\ &d.)\quad 861\hspace{.33em}\\~\\ \end{align}}\)
this = babaies
the slope of the hypotenuse is -1, so the "tops" of each column are integers 41,40,... ,0 if we start at x=1, the entire column has its top is at 40 the number of inside points are y=1 to 39 at x=2, its top is at 39, # of inside points are y=1 to 38 etc add up 39,38,37, down to 1
http://www.wolframalpha.com/input/?i=%5Csum%5Climits_%7Bk%3D1%7D%5E%28p-1%29+%28k-1%29 plugin p = 41
i just drew by hand and followed a pattern \(\large \color{black }{\begin{align} (0,0),(0,1),(1,0)\implies 0\hspace{.33em}\\~\\ (0,0),(0,2),(2,0)\implies 0\hspace{.33em}\\~\\ (0,0),(0,3),(3,0)\implies 1\hspace{.33em}\\~\\ (0,0),(0,4),(4,0)\implies 3\hspace{.33em}\\~\\ (0,0),(0,5),(5,0)\implies 6\hspace{.33em}\\~\\ (0,0),(0,6),(6,0)\implies 10\hspace{.33em}\\~\\ \cdots \text{which gives triangular numbers} \end{align}}\) \(\large \color{black }{\begin{align} \dfrac{(41-2)(41-2+1)}{2}\end{align}}\)
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