Evaluate (x + y)^0 for x = 4 and y = 3.
A. 0
B. 1
C. 2
D. 7
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Nnesha (nnesha):
x =4 so replace x by 4 and y by 3
and remember exponent rules!!
Nnesha (nnesha):
what would be your answer if there is 0 exponent ?
OpenStudy (anonymous):
(4+3) 7
OpenStudy (anonymous):
no 0
OpenStudy (acxbox22):
u dont really need to plug anything in since the expression is to the power of 0
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Nnesha (nnesha):
again my question is \(\color{blue}{\text{Originally Posted by}}\) @Nnesha
what would be your answer if there is 0 exponent ?
\(\color{blue}{\text{End of Quote}}\)
OpenStudy (alexandervonhumboldt2):
a^0=1
OpenStudy (alexandervonhumboldt2):
let me prove:
OpenStudy (anonymous):
the answer is 7
OpenStudy (alexandervonhumboldt2):
a^0=a^1/a^1
a^1/a^1=a/a=1
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OpenStudy (alexandervonhumboldt2):
the ansewer is not seven
OpenStudy (acxbox22):
|dw:1428175540753:dw|
Nnesha (nnesha):
nope @snickers23232
do you know exponent rules ?
OpenStudy (alexandervonhumboldt2):
anything in 0 exponent is 1
OpenStudy (alexandervonhumboldt2):
exept 0
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OpenStudy (anonymous):
no
=/
OpenStudy (anonymous):
so the answer is 1?
OpenStudy (alexandervonhumboldt2):
yes
Nnesha (nnesha):
whenever variable or number any number or variable raise to the 0 exponent answer always going to be 0 |dw:1428175647118:dw|