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Mathematics 17 Online
OpenStudy (bloomlocke367):

I have some general questions about exponential functions.

OpenStudy (quickstudent):

Type them please:)

OpenStudy (bloomlocke367):

Is the domain ALWAYS going to be all real numbers?

OpenStudy (bloomlocke367):

and I know that when you have \(y=ab^x\), the y-intercept is equal to (0,a) but what if you have, for example, \(y=4^x\), is there a way to find a, other than graphing it or making a table to find the y-intercept, thus finding a?

OpenStudy (bloomlocke367):

@rational

OpenStudy (bloomlocke367):

@quickstudent

OpenStudy (bloomlocke367):

@rational will you please come help? Nobody else is.

OpenStudy (amistre64):

1*4^x ... what is a?

OpenStudy (amistre64):

or, y=a when x=0 what is 4^0?

OpenStudy (bloomlocke367):

well 1, but how do I know it's 1*4 and not 2*2, is what I'm trying ask, I guess.

OpenStudy (amistre64):

because 4^x is defined as b^x

OpenStudy (amistre64):

1 * (2*2)^x is still 1*4^x

OpenStudy (amistre64):

1 * (2*2)^x is not 1*2*2^x

OpenStudy (bloomlocke367):

Oh, okay.

OpenStudy (amistre64):

the exponent is a grouping symbol ( )^x whatever is inside of it is grouped and you must follow the order of operations

OpenStudy (bloomlocke367):

That makes more sense. So, if it doesn't have something like \(y=12(0.95)^x\), is a automatically 1?

OpenStudy (bloomlocke367):

In that equation, a is 12... but if it's not split up, it's 1, correct?

OpenStudy (amistre64):

yes, mathmatikers dont like writing a 1 in front of things. 1*x means that we have only one x; so 1*x = x

OpenStudy (amistre64):

yes, a=12 in that case, if its not split then its 1

OpenStudy (bloomlocke367):

Okay. See, I'm learning this on my own, and I want to make sure I'm not teaching myself incorrectly XD

OpenStudy (amistre64):

itll be fine :)

OpenStudy (bloomlocke367):

I have more questions :D I'm a question asker. xp

OpenStudy (bloomlocke367):

So, will the x-axis always be an asymptote?

OpenStudy (amistre64):

no

OpenStudy (amistre64):

if we move the function up or down, we move the asymptote

OpenStudy (amistre64):

y = ab^x + k has an asymptote as y=k

OpenStudy (bloomlocke367):

Ohhh, I haven't gotten that far in my textbook, I guess.

OpenStudy (bloomlocke367):

It says that if a>0 and b>1, that the function represents an exponential growth and that if a>0 and 0<b<1 it represents an exponential decay... but what if a<0?

OpenStudy (bloomlocke367):

I think I may be getting ahead of myself... sorry.

OpenStudy (amistre64):

if a is <0 youve flipped the graph upside down ...

OpenStudy (amistre64):

ab^0 = a*1 -ab^0 = -a*1

OpenStudy (amistre64):

if b = 1/c (1/c)^x = c^(-x)

OpenStudy (bloomlocke367):

I understand what you mean by flipping the graph, but what do you mean by the last thing you put? @amistre64

OpenStudy (amistre64):

have you worked with fraction before?

OpenStudy (amistre64):

the x variable is the rate of change if its negative, we are decreasing if its positive, we are increasing if b is a value between 0 and 1, then its essentially a fraction applying fraction rules, we just see that we can get a -x to indicate it is decreasing is all

OpenStudy (amistre64):

if b=1/3 (1/3)^(x) = 3^(-x)

OpenStudy (bloomlocke367):

ohhhhhhh. okay.

OpenStudy (bloomlocke367):

Thank you.

OpenStudy (amistre64):

your welcome

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