Stuck in this one In how many ways 5 boys be seated in a row if two of them refused tp sit together?
which 2? is it just 2 that are refusing? maybe split it up into cases
Ya 2 boys refused to sit together
a bbb k , there are 3! ways to set that up, b a bb k , there are 2! ways to set that up, bb a b k , there are 2! ways to set that up, bbb ak , there are no ways to set that up bbb ka , there are no ways to set that up and each way can be flipped around so 2 ways per case right? or what is my error
The question is there r 5 boys and 5 seats , two the boys refuse to sit together
a bbb k a bbk b a bkb b b abb k b abk b b bab k k bab b b bba k .... eww, gotta move b kba b k bba b b bbk a .... eww, gotta move b bkb a b kbb a k bbb a
but then the other 3 boys dont care, so they can shift about as needed right?
Ya
so, b1 b2 b3 can be seated in how many orders?
12 ways to order 3 boys is what this boils don to
3! Of three boys
Its statistic qts
12*3! should do it then
Id think so :/
im just tossing ideas, i cant say for sure what approach is the best tho
if we have covered all the ways that the boys will sit, then each sitting has 3! ways to arrange the remaining boys, seems fair to me
Tnx man but i need the correct answer
Appreciate ur help (y)
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