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Mathematics 19 Online
OpenStudy (anonymous):

Stuck in this one In how many ways 5 boys be seated in a row if two of them refused tp sit together?

OpenStudy (amistre64):

which 2? is it just 2 that are refusing? maybe split it up into cases

OpenStudy (anonymous):

Ya 2 boys refused to sit together

OpenStudy (amistre64):

a bbb k , there are 3! ways to set that up, b a bb k , there are 2! ways to set that up, bb a b k , there are 2! ways to set that up, bbb ak , there are no ways to set that up bbb ka , there are no ways to set that up and each way can be flipped around so 2 ways per case right? or what is my error

OpenStudy (anonymous):

The question is there r 5 boys and 5 seats , two the boys refuse to sit together

OpenStudy (amistre64):

a bbb k a bbk b a bkb b b abb k b abk b b bab k k bab b b bba k .... eww, gotta move b kba b k bba b b bbk a .... eww, gotta move b bkb a b kbb a k bbb a

OpenStudy (amistre64):

but then the other 3 boys dont care, so they can shift about as needed right?

OpenStudy (anonymous):

Ya

OpenStudy (amistre64):

so, b1 b2 b3 can be seated in how many orders?

OpenStudy (amistre64):

12 ways to order 3 boys is what this boils don to

OpenStudy (anonymous):

3! Of three boys

OpenStudy (anonymous):

Its statistic qts

OpenStudy (amistre64):

12*3! should do it then

OpenStudy (anonymous):

Id think so :/

OpenStudy (amistre64):

im just tossing ideas, i cant say for sure what approach is the best tho

OpenStudy (amistre64):

if we have covered all the ways that the boys will sit, then each sitting has 3! ways to arrange the remaining boys, seems fair to me

OpenStudy (anonymous):

Tnx man but i need the correct answer

OpenStudy (anonymous):

Appreciate ur help (y)

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