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Mathematics 22 Online
OpenStudy (surana):

Which point is contained in the graph of y > lx-2l - 1?

OpenStudy (surana):

The l's between the x-2 represent absolute value, just to clarify.

OpenStudy (korosh23):

What are you trying to find?

OpenStudy (surana):

Trying to find the point that is in the graph, y > lx-2l - 1.

OpenStudy (surana):

I made a question like this earlier but I forgot to add the absolute value in it.

OpenStudy (korosh23):

You know that \[y > \left| x-2 \right|-1\] \[y > x -3\]

OpenStudy (korosh23):

Is this your point? Or are you looking for the x and y-intercepts?

OpenStudy (surana):

I believe I still need to look for the x and y intercepts.

OpenStudy (korosh23):

Ok so that is now clear to me :)

OpenStudy (surana):

I believe the answer is supposed to be in (number, number) form.

OpenStudy (surana):

Since they're looking for a point.

OpenStudy (korosh23):

When you want to find the y-inercept, x intercept has to be zero Ex: \[Y >(0) -3\]

OpenStudy (korosh23):

y is > -3

OpenStudy (surana):

Y is greater than -3, so I still need to keep going, right?

OpenStudy (korosh23):

yes I believe. However y always have to equal to something in order to find the x-intercepts

OpenStudy (surana):

So at the moment, we have -3 in the x section?

OpenStudy (korosh23):

No y is -3 which shows you where the line crossed the y axes

OpenStudy (surana):

Oh.

OpenStudy (korosh23):

Now we look for x-intercepts which we have to find it like this \[0 > x -3\]

OpenStudy (korosh23):

3> x

OpenStudy (surana):

So I isolate one side?

OpenStudy (korosh23):

Yes you isolate one side and you get x intercept < 3

OpenStudy (surana):

So X is 3.

OpenStudy (korosh23):

yes

OpenStudy (korosh23):

Do you have graphing calculator?

OpenStudy (surana):

Yeah. Should I go get it?

OpenStudy (korosh23):

It is a good idea to use it

OpenStudy (surana):

Well, I have it with me now.

OpenStudy (surana):

So what now?

OpenStudy (korosh23):

Now plug in the equation

OpenStudy (surana):

Could you walk me through this please? I need to remember which buttons to press.

OpenStudy (korosh23):

Check this out. By the way do you have access to youtube?

OpenStudy (korosh23):

OpenStudy (surana):

Mine's a different one.

OpenStudy (korosh23):

which model is it?

OpenStudy (surana):

It's a fx-9750GII.

OpenStudy (korosh23):

hmmmm ley me see, do you have android system phone?

OpenStudy (surana):

No. We could just work it out here if it'll help.

OpenStudy (korosh23):

Well I do not known how to use that. I got to go now. I suggest go in youtube and type your model graphing calculator. I just checked it, there are tons of examples with how to use it. I hope I helped @Surana

OpenStudy (surana):

That'll do. Thanks. I'll leave this one up and see if someone else can help out.

OpenStudy (korosh23):

No problem! :)

OpenStudy (anonymous):

what are trying to solve ?

OpenStudy (surana):

I'm trying to solve to see which point is in the graph of Y > lx2l - 1.

OpenStudy (anonymous):

recheck question its different from the one u posted

OpenStudy (surana):

Gah. The question was "Which point is contained in the graph of y > lx-2l -1?"

OpenStudy (anonymous):

u know how to draw graph

OpenStudy (surana):

Yes.

OpenStudy (anonymous):

then draw the graph of right hand side

OpenStudy (surana):

I got 2, -1 as an answer, but I think that one is incorrect.

OpenStudy (surana):

Wait, absolute value means it's positive, so if 2,-1 is the answer, then it should be (2,1)?

OpenStudy (surana):

So I should look for an answer that's positive. Okay.

OpenStudy (surana):

What?

OpenStudy (anonymous):

@dan815

OpenStudy (surana):

Oh.

OpenStudy (surana):

Who's he?

OpenStudy (anonymous):

a qualified helper

OpenStudy (surana):

Thank you. I'll take a look around.

OpenStudy (anonymous):

@k_lynn

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