Which point is contained in the graph of y > lx-2l - 1?
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OpenStudy (surana):
The l's between the x-2 represent absolute value, just to clarify.
OpenStudy (korosh23):
What are you trying to find?
OpenStudy (surana):
Trying to find the point that is in the graph, y > lx-2l - 1.
OpenStudy (surana):
I made a question like this earlier but I forgot to add the absolute value in it.
OpenStudy (korosh23):
You know that \[y > \left| x-2 \right|-1\]
\[y > x -3\]
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OpenStudy (korosh23):
Is this your point? Or are you looking for the x and y-intercepts?
OpenStudy (surana):
I believe I still need to look for the x and y intercepts.
OpenStudy (korosh23):
Ok so that is now clear to me :)
OpenStudy (surana):
I believe the answer is supposed to be in (number, number) form.
OpenStudy (surana):
Since they're looking for a point.
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OpenStudy (korosh23):
When you want to find the y-inercept, x intercept has to be zero
Ex: \[Y >(0) -3\]
OpenStudy (korosh23):
y is > -3
OpenStudy (surana):
Y is greater than -3, so I still need to keep going, right?
OpenStudy (korosh23):
yes I believe. However y always have to equal to something in order to find the x-intercepts
OpenStudy (surana):
So at the moment, we have -3 in the x section?
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OpenStudy (korosh23):
No y is -3 which shows you where the line crossed the y axes
OpenStudy (surana):
Oh.
OpenStudy (korosh23):
Now we look for x-intercepts
which we have to find it like this
\[0 > x -3\]
OpenStudy (korosh23):
3> x
OpenStudy (surana):
So I isolate one side?
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OpenStudy (korosh23):
Yes you isolate one side and you get x intercept < 3
OpenStudy (surana):
So X is 3.
OpenStudy (korosh23):
yes
OpenStudy (korosh23):
Do you have graphing calculator?
OpenStudy (surana):
Yeah. Should I go get it?
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OpenStudy (korosh23):
It is a good idea to use it
OpenStudy (surana):
Well, I have it with me now.
OpenStudy (surana):
So what now?
OpenStudy (korosh23):
Now plug in the equation
OpenStudy (surana):
Could you walk me through this please? I need to remember which buttons to press.
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OpenStudy (korosh23):
Check this out. By the way do you have access to youtube?
OpenStudy (korosh23):
OpenStudy (surana):
Mine's a different one.
OpenStudy (korosh23):
which model is it?
OpenStudy (surana):
It's a fx-9750GII.
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OpenStudy (korosh23):
hmmmm ley me see, do you have android system phone?
OpenStudy (surana):
No. We could just work it out here if it'll help.
OpenStudy (korosh23):
Well I do not known how to use that. I got to go now.
I suggest go in youtube and type your model graphing calculator. I just checked it, there are tons of examples with how to use it. I hope I helped @Surana
OpenStudy (surana):
That'll do. Thanks. I'll leave this one up and see if someone else can help out.
OpenStudy (korosh23):
No problem! :)
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OpenStudy (anonymous):
what are trying to solve ?
OpenStudy (surana):
I'm trying to solve to see which point is in the graph of Y > lx2l - 1.
OpenStudy (anonymous):
recheck question its different from the one u posted
OpenStudy (surana):
Gah. The question was "Which point is contained in the graph of y > lx-2l -1?"
OpenStudy (anonymous):
u know how to draw graph
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OpenStudy (surana):
Yes.
OpenStudy (anonymous):
then draw the graph of right hand side
OpenStudy (surana):
I got 2, -1 as an answer, but I think that one is incorrect.
OpenStudy (surana):
Wait, absolute value means it's positive, so if 2,-1 is the answer, then it should be (2,1)?
OpenStudy (surana):
So I should look for an answer that's positive. Okay.
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OpenStudy (surana):
What?
OpenStudy (anonymous):
@dan815
OpenStudy (surana):
Oh.
OpenStudy (surana):
Who's he?
OpenStudy (anonymous):
a qualified helper
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