Solve the quadratic equation 5x^2 -125 = 0.
The ^2 represents Exponent of 2.
hint: \[5{x^2} - 125 = 5\left( {{x^2} - {5^2}} \right) = 5\left( {x - 5} \right)\left( {x + 5} \right)\]
That'll help, thanks.
thanks!
You're welcome.
thanks! :)
I'm just going to solve it on a piece of paper and then come back with the answer.
Not a lot more work can be done on paper. :P You just now have to set each one to 0, to find the roots (or the value of x) :)
Not a lot more work can be done on paper. :P You just now have to set each one to 0, to find the roots (or the value of x) :)
Set to zero?
\(\sf 5(x+5)(x-5)\) And then to find the value of x: \(\sf (x+5)=0\) and \(\sf (x-5)=0\) And solve for x in both equations, and you should have two values for x as your answer :)
5(x+5)(x−5) And then to find the value of x: (x+5)=0 and (x−5)=0 And solve for x in both equations, and you should have two values for x as your answer :)
So I have to multiply x+5 by 5 and then put five on the side of x and then divide?
No, you just subtract 5 on both sides. And for the other equation, you add 5 to both sides. :)
No, you just subtract 5 on both sides. And for the other equation, you add 5 to both sides. :)
Thank you, I will work that out then.
I got -5 and +5.
Correct. :) So now if you wanted to test out those answers, then plug in x=5 and x=-5 into the original equation, and it would equal to 0! :)
that's right!
uh yae
So one of those two is the answer, I'll check, then.
both of those numbers are the answer
^
The thing is that the answers I'm allowed is that only one of those can be chosen. I still don't know which one to choose.
I think I'll go with -5.
Do you have answer choices? If the answer box is a blank then try putting `5, -5`
is there a choice for \(\pm\)5?
Yeah, there is.
is x a length?
Does that mean both positive and negative?
yes, it does
Then I'll go with that one instead.
:)
Thank you all!
I'll close the question now.
good luck with your future math things :*
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