Question

Simplify the factorial Expression: (2n-1)!/(2n+1)!
How do you solve it??

Answer 1

subtract one until you get same parenthesesat the denominator & numerator to cancel out :D

Answer 2

can you show me please

Answer 3

\[\huge\rm \frac{ (2n-1)! }{ (2n+1)! }\]
(2n-1)-1
or
(2n +1) -1

Answer 4

keep subtracting one until you can cancel something :)
is that make sense ?
seems like nope :

Answer 5

where are you getting the one from

Answer 6

that's the rule you have to subtract 1 for example
if there are numbers \[\huge\rm \frac{ 4! }{ 3! } = \frac{ 4 \times 3 \times 2 \times 1 }{ 3 \times 2 \times 1 }\]
4-1 =3
3-1=2
2-1=1

Answer 7

so (2(-1)-1)-1/(2(-1)+1)-1

Answer 8

nope you don't have to replace n by -1
\[\large\rm (2n+1)\color{red}{-1} = 2n +1\color{red}{-1}\]

Answer 9

combine like terms
+1-1 = 0 so 2n left
\[\rm \frac{ (2n-1)! }{ (2n+1)2n! }\]
now subtract again
(2n ) -1

Answer 10

ok

Answer 11

1/2n(2n+1)

Answer 12

how did you get 1 at the numerator ?

Answer 13

-1

Answer 14

thats the answer in the back of the book

Answer 15

nope like i said you have to cancel something
so to do that subtract from (2n+1)!

Answer 16

yep but i'm asking how did you get :)

Answer 17

i dont understand :(

Answer 18

\[\rm \frac{ (2n-1)! }{ (2n+1\color{red}{-1})(2n\color{red}{-1})! }\]

subtract one

Answer 19

ik :( wait... i should tag some factorial experts...

Answer 20

ok

Answer 21

@amistre64

Answer 22

dont worry about it ill just ask the teacher about it

Answer 23

\[(2n+1\color{red}{-1}) = 2n\]
then subtract one again
\[(2n)\color{Red}{-1} = (2n-1)\]
now 2n-1 is at the denominator and at the numerator so you cancel out that