I need help with a differential equation (1+y^2)(e^(2x) dx - e^y dy)-(1+y)dy = 0
\[(1+y^2)(e ^{2x}dx - e^y dy) - (1 +y)dy=0\]
that looks separable
Are thete any answer choices?
\[e ^{2x}dx - e^y dy = \frac{ dy + y dy }{ 1+y^2 }\]
This is something new we are seeing in class and I'm unsure as to how I should approach it.
collect terms attached to `dx` on one side and terms attached to `dy` on other side
Is that thr equation or answer choice?
no answer choice
get it into this form : (stuff) `dy` = (stuff) `dx`
\[e ^{2x}dx = \frac{ dy+y dy }{ 1+y^2 }+ e^y dy\]
all `dy` s must be on one side
all `dx` must be on other side
I have all dx on the left side and dy on the right side
Ahh nice :) simply integrate now
\[\int e ^{2x}dx = \int \frac{ (1+y) dy }{ 1+y^2 }+\int e^y dy\]
oo I see what you are doing.
\[\frac{ 1 }{ 2 }e^{2x}=\tan^{-1}(y)+\frac{ 1 }{ 2 } \ln|1+y^2|+e^y \]
@rational just a little question, is this all to it?meaning that this falls as a "separable category" where it ends as a general solution such as x(x) + y (y) = C?
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