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Can someone please explain this to me? Use the function to answer the question. What is the value of h(1)? 1 0 1 2
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h maps (k) to (k^2-k)
so h takes an input value and produces an output value ..... it functions on whatever k is
if we insert (1) into h, then k=1 ... what is the output?
Okay so h is the domain and k is the range?
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h is the name of the function, think of it as y if it helps k is the domain, (k^2-k) is the range
h(k) = k^2-k what is h(k=1) or simply, h(1)
Okay, I think the answer is one, correct?
what is 1^2-1 ?
Okay, zero. That was my first answer but I second guessed myself.
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well, third guess it back to zero :)
Sorry, that confused me. I am not sure if I follow...
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