Question

Can someone please explain this to me?

Use the function to answer the question.

What is the value of h(1)?

1

0

1

2

Answer 1

h maps (k) to (k^2-k)

Answer 2

so h takes an input value and produces an output value ..... it functions on whatever k is

Answer 3

if we insert (1) into h, then k=1 ... what is the output?

Answer 4

Okay so h is the domain and k is the range?

Answer 5

h is the name of the function, think of it as y if it helps

k is the domain, (k^2-k) is the range

Answer 6

h(k) = k^2-k

what is h(k=1) or simply, h(1)

Answer 7

Okay, I think the answer is one, correct?

Answer 8

what is 1^2-1 ?

Answer 9

Okay, zero. That was my first answer but I second guessed myself.

Answer 10

well, third guess it back to zero :)

Answer 11

Sorry, that confused me. I am not sure if I follow...