Help find the area in these two shapes? C:

Question

anonymous · Answer

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e.mccormick · Answer

For any parallelogram, it is the height times the base.  Works for squares, rectangles, and even the odd shaped ones.

For trapezoids, it is slightly different because you take the average of both bases... but in a paralleolgram the bases are the same so their average is their length.

e.mccormick · Answer

For the rectangle, they give you the diagonal.  So use that to find the height.

igreen · Answer

A = bh

A = (17)(6)

igreen · Answer

For the 2nd one, use the Pythagorean Theorem to find the length of the rectangle.

igreen · Answer

$a^2 + b^2 = c^2$

The diagonal is the hypotenuse, and 18 is one of the legs.

$a^2 + 18^2 = 30^2$

Solve for 'a', then multiply it by 18 to get the area.

igreen · Answer

Can you take over from here? @CrazyCountryGirl

anonymous · Answer

#1 is 102?
#2 is 432?
@e.mccormick @iGreen

igreen · Answer

Yep!

17 * 6 = 102

18^2 = 324
30^2 = 900

900 - 324 = 576

Square root of 576 = 24

24 * 18 = 432