Question

Evaluate each expression: Explain how to work it out. *Problems will be in comment box*

Answer 1

@dan815 @goformit100

Answer 2

For the first question, 11^(n-5) = 11 and n-5 has to be equal to 1 for 11 to equal 11, so n is equal to 6

Answer 3

how did you get that?:

\[11^(n - 5) = 11\]

Answer 4

how does n - 5 have to equal 1 for 11 to = 11 so n = 6

Answer 5

so basic log properties say that \[\log _{b}x = y \] is the same thing as \[x = b ^{y}\] and in this case, b= 11, x = 11, and y = (n-5) and if you change it into the exponent form from the log form, then you can solve for n

Answer 6

so when \[11^{(n-5)} = 11\] then n-5 has to be 1 and n is equal to 6

Answer 7

Are dividing 11 by 11 to get one like how are you getting 1?