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OpenStudy (anonymous):
What is the Molarity of a H+1 ion of a 0.0001M KOH solution?
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OpenStudy (sweetburger):
KOH is a strong base so if you take the -log(.0001) you will get the pOH take that value and subtract it from 14 and you will have the pH when you have the pH plug it into the equation of 10^-pH
OpenStudy (sweetburger):
using the final equation once all the steps have been completed should give you the concentration of H+ ions
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