Question

Help with no. 1 pleaseee! http://wenku.baidu.com/view/ae804322ccbff121dd368328

Answer 1

@perl

Answer 2

which problem

Answer 3

Number 1

Answer 4

the first section

Answer 5

Yes

Answer 6

I've found w = -1/2 + i sqrt3 /2

Answer 7

Couldn't find uw and u/w

Answer 8

$$ \Large {w = 1[cos( \frac{2\pi}{3}) + i \sin(\frac{2\pi}{3}]
=-\frac12 + i\cdot \frac{\sqrt3}{2}

\\~~\\
u\cdot w = 2i ( -\frac12 + i\cdot \frac{\sqrt3}{2}) = -i -\sqrt{3}


} $$

Answer 9

What about iii)?

Answer 10

U/w? Do I put 2i/ -1/2 + I sqrt3/2 ??

Answer 11

yes

Answer 12

iii Pls.

Answer 13

$$ \Large {
\frac{2i }{ -\frac12 + i\cdot \frac{ \sqrt{3} } {2}}
= \frac {2\cdot 2i}{-1 + i \sqrt3 }


} $$

Answer 14

ok so far?

Answer 15

$$ \Large {
\frac{2i }{ -\frac12 + i\cdot \frac{ \sqrt{3} } {2}} \\
=\frac{2i }{\left( -\frac12 + i\cdot \frac{ \sqrt{3} } {2} \right)} \cdot \frac{2}{2}
= \frac {2\cdot 2i}{-1 + i \sqrt3 } \\
=\frac {2\cdot 2i}{-1 + i \sqrt3 } \cdot \frac{-1 - i \sqrt3}{-1 - i \sqrt3} \\


} $$

Answer 16

Oh yes I'm good with that alrd. I mean help me with iii :)

Answer 17

the equilateral triangle?

Answer 18

Yasss

Answer 19

it is equilateral if | U- A | = | U - B | = | A - B|

Answer 20

show that $$ \Large { | w - uw | = | w - \frac{u}{w}|= | uw - \frac uw | }$$

Answer 21

Oh. That's all?

Answer 22

U is u btw

Answer 23

yes

Answer 24

Thanks. Help me with 8 iii Pls :)

Answer 25

i can't read that , its a bit hazy

Answer 26

Clear now?

Answer 27

its upside down

Answer 28

AH, I give up alrd lol. It's okay