Solve: (x + 1)2 = 9
A. -2, 4
B. 2, -4
C. 2, 4
D. 1, -4
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OpenStudy (anonymous):
@Michele_Laino
OpenStudy (michele_laino):
hint:
if we take the square root of both sides, we get the subsequent equations:
\[\large \begin{gathered}
x + 1 = 3 \hfill \\
x + 1 = - 3 \hfill \\
\end{gathered} \]
since we have:
\[\sqrt 9 = \pm 3\]
OpenStudy (michele_laino):
we have to solve those equations
OpenStudy (michele_laino):
for example, let's consider the first equation:
x+1=3
If I subtract +1 from both sides, I get:
\[\large x + 1 - 1 = 3 - 1\]
OpenStudy (michele_laino):
what is x?
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OpenStudy (anonymous):
2?
OpenStudy (michele_laino):
ok!
OpenStudy (michele_laino):
that's the first solution.
Now let's consider the second equation:
x+1=-3
again I subtract +1 from both sides, and I get:
\[\large x + 1 - 1 = - 3 - 1\]
what is x?
OpenStudy (anonymous):
Oh I just realized that when I pasted the problem it changed the format. (x + 1)^2 = 9 is what it should be. The 2 is an exponent
OpenStudy (michele_laino):
yes!
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OpenStudy (anonymous):
Okay?
OpenStudy (michele_laino):
ok!
OpenStudy (anonymous):
SO what next?
OpenStudy (michele_laino):
what is x, from the second equation?
OpenStudy (anonymous):
-4
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OpenStudy (michele_laino):
\[\large x + 1 - 1 = - 3 - 1\]
OpenStudy (michele_laino):
ok!
OpenStudy (michele_laino):
so, what is the right option?
OpenStudy (anonymous):
2,-4, or B
OpenStudy (michele_laino):
that's right!
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