I think I have this figured out, but I'm not sure. Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 9 sin 7\(\theta\)
I know this is the graph, and I think it is the y-axis only http://prntscr.com/6r0ryy
If that is the graph, it is correct, but let me check :)
After checking ( https://www.wolframalpha.com/input/?i=r+%3D+9+sin+7%CE%B8), I think you are right. But you should try some values to be sure, you should not base your answers purely on graphs
Okay, thanks :)
To understand whether a graph is symmetric about which axis, you might want to start by plugging in points. \[\text{symmetric about x-axis} \implies (x,y) \rightarrow (x,-y)\]\[\text{symmetric about the y-axis} \implies (x,y) \rightarrow (-x,y)\]\[\text{symmetric about the origin} \implies (x,y) \rightarrow (-x,-y)\]
Thanks to both of you :)
In this case, \((x,y) \rightarrow (r,\theta)\)
For further reference, this might help you http://www.saylor.org/site/wp-content/uploads/2011/04/GRAPHING-IN-POLAR-COORDINATES.pdf
Okay :D
It's also good to remember your even and odd functions: Even function: \(f(-x)=f(x)\) odd function: \(f(-x)=-f(x)\)
\[\sin(-x)=-\sin(x)\]\[\cos(-x)=\cos(x)\]\[\tan(-x)=-\tan(x)\]
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