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Mathematics 16 Online
OpenStudy (ohohaye):

Can someone please help me with solving on the interval?

OpenStudy (ohohaye):

OpenStudy (anonymous):

whats sin(pi/2)?

OpenStudy (ohohaye):

In degrees?

OpenStudy (anonymous):

do you know the unit circle?

OpenStudy (ohohaye):

yeah

OpenStudy (anonymous):

can you use it to find sin(pi/2)?

OpenStudy (ohohaye):

its (0, 1) right?

OpenStudy (anonymous):

its 1 for sin and 0 for cos

OpenStudy (ohohaye):

Yeah

OpenStudy (anonymous):

so for sin(pi/2) just replace that with one in the equation and see if it equals 0

OpenStudy (anonymous):

|dw:1428466815493:dw|

OpenStudy (ohohaye):

yep, it equals 0

OpenStudy (anonymous):

great, that means x=pi/2 is a solution.

OpenStudy (anonymous):

now try it with pi/6

OpenStudy (ohohaye):

(root3/2, 1/2)

OpenStudy (anonymous):

ok, one is cos(pi/6) and the other is sin(pi/6). can you tell me which one represents sin(pi/6)?

OpenStudy (ohohaye):

(1/2)

OpenStudy (ohohaye):

Right?

OpenStudy (anonymous):

yep, good job

OpenStudy (anonymous):

do you know where those values come from? what the sine and cosine functions look like?

OpenStudy (ohohaye):

I think so, isn't cosine 1, 1 and sine 1, 2 Right?

OpenStudy (anonymous):

ummm, i'm not sure what you mean

OpenStudy (anonymous):

so that's what the sine function looks like

OpenStudy (ohohaye):

oh ok, I thought you meant something else

OpenStudy (anonymous):

at pi/2 the height of the graph is at one

OpenStudy (anonymous):

at pi/6 the height of the graph is at 1/2

OpenStudy (ohohaye):

wait so the first one is the answer?

OpenStudy (anonymous):

we don't know that yet

OpenStudy (anonymous):

try plugging in 1/2 for sinx in the equation and see if it equals 0

OpenStudy (anonymous):

like we did before for sin(pi/2)

OpenStudy (anonymous):

|dw:1428468136019:dw|

OpenStudy (ohohaye):

It equals 0

OpenStudy (anonymous):

thats right, x=pi/6 is a solution

OpenStudy (anonymous):

so what's sin(5pi/6)?

OpenStudy (ohohaye):

(1/2)

OpenStudy (anonymous):

that's right, well done

OpenStudy (ohohaye):

So we have (pi/2), (pi/6), and (5pi/6) right?

OpenStudy (anonymous):

yes

OpenStudy (ohohaye):

Thank you so much

OpenStudy (anonymous):

no problem, have a good night.

OpenStudy (ohohaye):

You too

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