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OpenStudy (bibby):
plug the result of g(2) into f(x)
OpenStudy (bizzeizzy):
so x=2?
OpenStudy (bibby):
yeah
OpenStudy (bizzeizzy):
f(2)= 2+3 and g(2)=4(2)?
OpenStudy (bibby):
we're not touching f(x)
in function composition \(f(g(x))\) means evaluating \(g(x)\) and plugging the result into \(f(x)\).
first find g(2). you say it's 4(2). looks right
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OpenStudy (bizzeizzy):
do i solve that or no?
OpenStudy (bibby):
well, yeah...
OpenStudy (bizzeizzy):
ok, 6.
OpenStudy (bibby):
not exactly
OpenStudy (bizzeizzy):
then what do you mean?
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OpenStudy (bizzeizzy):
i'm confused.
OpenStudy (bibby):
you're multiplying not adding. \(4(2)=4 \times 2\)
OpenStudy (bizzeizzy):
omg blonde moment!! 8
OpenStudy (bibby):
I can't wait till I'm fully bald so that I can make blonde moment jokes that have 2 layers
OpenStudy (bibby):
so now we have to evaluate f(8)
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OpenStudy (bizzeizzy):
hahahahahah
and what does that mean?
OpenStudy (bibby):
I don't understand how little you know about functions. If I asked you what the value of f(2) is what would you say?
OpenStudy (bibby):
that sounds mean
I meant I don't know where to start explaining if I don't know what you don't know
OpenStudy (bibby):
ya know?
OpenStudy (bizzeizzy):
i have no clue how do do any of this
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OpenStudy (bibby):
a function takes a value and outputs another value. there are other technicalities but that's the basic definition we need here.
here, \(f(x)=x+3\), right?
that means wherever we see an x, we replace it with the number we're plugging into the function to evaluate.
for example: \(f(x)=x+3\\f(2)=2+3\\f(5)=5+3\) etc.