What is the factored form of 5x^2+19x-4?

Question

anonymous · Answer

5 x -4 = -20 
now we have to split  +19 in two parts [b1 and b2] in such a way that the summation of b1+b2 given 19 and their product gives -20 
so  19 = 20-1    such that 20 x (-1) = -20 
hence 5x^2 +20x - x -4 = 0 
now take common ... hope you can do from here

anonymous · Answer

If you weren't able to do it from there the factored form would be (x + 4) (5x - 1). Btw good job explaining @digitalmonk :)

anonymous · Answer

you have me confused 5x-4   =-20   where did that come from

anonymous · Answer

(5x-1)(x+4) is much easier

anonymous · Answer

I explained you the process. 
5x^2 +20x - x -4 = 0 
5x(x+4) -1(x+4) = 0 
i.e. (x+4)(5x-1) = 0  [taking x+4 as common] 
so either x+4 =0  which means x = -4 
or (5x-1) = 0 which means x = - 1/5