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Mathematics 23 Online
OpenStudy (ohohaye):

I need help please

OpenStudy (ohohaye):

OpenStudy (bibby):

a product is = to 0 if either term is 0, for example ab=0 when either a=0 or b=0 set each individual term = 0 and solve

OpenStudy (ohohaye):

So each term has to equal 0?

OpenStudy (bibby):

yeah. \(\cos(x)=0\\\cos(x)-1=0\)

OpenStudy (ohohaye):

So I would type cos(1/2)(cos(1/2)-1) in a calculator?

OpenStudy (bibby):

why a half?

OpenStudy (ohohaye):

That is one cos variables on the unit circle

OpenStudy (ohohaye):

So do I type that into the calculator?

OpenStudy (bibby):

the way to read that is \(\cos(\dfrac{\pi}{2})=0\)

OpenStudy (bibby):

and so for cos x = 0, x=pi/2 +2npi

OpenStudy (ohohaye):

I don't get it

OpenStudy (bibby):

err pi n

OpenStudy (bibby):

what don't you get? the \(\pm\) is the period

OpenStudy (ohohaye):

I'm still confused...

OpenStudy (bibby):

basically, you have it right

OpenStudy (ohohaye):

ok, so I just type it in the way you said?

OpenStudy (bibby):

type what out? your work?

OpenStudy (ohohaye):

No into the calculator

OpenStudy (bibby):

oh, you should be using \(\cos^{-1}(x)\) or the \(arccos\) buttons

OpenStudy (ohohaye):

ok

OpenStudy (bibby):

and so for the first one, we have \(cos(x)=0\\arccos(cos(x))=arccos(0)\\x=arccos(0)\\x=\dfrac{\pi}{2}\)

OpenStudy (ohohaye):

ok, I think I have it now, thank you for the help

OpenStudy (bibby):

similarly arccos(1)=2pi

OpenStudy (ohohaye):

Thank you again for the help

OpenStudy (bibby):

anytime

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