Mathematics
23 Online
OpenStudy (ohohaye):
I need help please
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OpenStudy (ohohaye):
OpenStudy (bibby):
a product is = to 0 if either term is 0, for example ab=0 when either a=0 or b=0
set each individual term = 0 and solve
OpenStudy (ohohaye):
So each term has to equal 0?
OpenStudy (bibby):
yeah. \(\cos(x)=0\\\cos(x)-1=0\)
OpenStudy (ohohaye):
So I would type cos(1/2)(cos(1/2)-1) in a calculator?
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OpenStudy (bibby):
why a half?
OpenStudy (ohohaye):
That is one cos variables on the unit circle
OpenStudy (ohohaye):
So do I type that into the calculator?
OpenStudy (bibby):
the way to read that is \(\cos(\dfrac{\pi}{2})=0\)
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OpenStudy (bibby):
and so for cos x = 0, x=pi/2 +2npi
OpenStudy (ohohaye):
I don't get it
OpenStudy (bibby):
err pi n
OpenStudy (bibby):
what don't you get? the \(\pm\) is the period
OpenStudy (ohohaye):
I'm still confused...
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OpenStudy (bibby):
basically, you have it right
OpenStudy (ohohaye):
ok, so I just type it in the way you said?
OpenStudy (bibby):
type what out? your work?
OpenStudy (ohohaye):
No into the calculator
OpenStudy (bibby):
oh, you should be using \(\cos^{-1}(x)\) or the \(arccos\) buttons
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OpenStudy (ohohaye):
ok
OpenStudy (bibby):
and so for the first one, we have \(cos(x)=0\\arccos(cos(x))=arccos(0)\\x=arccos(0)\\x=\dfrac{\pi}{2}\)
OpenStudy (ohohaye):
ok, I think I have it now, thank you for the help
OpenStudy (bibby):
similarly arccos(1)=2pi
OpenStudy (ohohaye):
Thank you again for the help
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OpenStudy (bibby):
anytime