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Geometry 26 Online
OpenStudy (pagen13):

What are a) the ratio of the perimeters and b) the ratio of the areas of the larger figure to the smaller figure? a. 5/2 and 25/4 b. 5/2 and 7/4 c. 7/2 and 25/4 d. 7/2 and 7/4

OpenStudy (pagen13):

OpenStudy (pagen13):

@sammixboo @Cicilybailey14 can you help?

OpenStudy (anonymous):

Question, is the number assigned to the shapes already the perimeter?

OpenStudy (anonymous):

or is it the area?

OpenStudy (anonymous):

@Pagen13 Answer please

OpenStudy (pagen13):

the perimeter i think?

OpenStudy (anonymous):

ok well the for the first one, it's as easy as dividing the bigger one by the smaller one then simplifying

OpenStudy (anonymous):

so, 30/12 15/6 5/2

OpenStudy (pagen13):

Okay so the first one is 5/2 how do i find the second part?

OpenStudy (anonymous):

well, I would go with logic.

OpenStudy (anonymous):

We already eliminated 2 of those answers

OpenStudy (pagen13):

a?

OpenStudy (anonymous):

and we know tat the second shape is aprox twice the size as the smaller one

OpenStudy (pagen13):

right. So the answer is A

OpenStudy (anonymous):

I think so

OpenStudy (pagen13):

Can you help with a couple more?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

are you a VLACS or FLVS student?

OpenStudy (pagen13):

The area of a regular hexagon is 38cm2. What is the area of the regular hexagon with sides four times as long? a. 152cm2 b. 228cm2 c. 304cm2 d. 608cm2 And no i am not

OpenStudy (anonymous):

oh ok Let's see... we want the area?

OpenStudy (pagen13):

yes

OpenStudy (anonymous):

Sorry, I didn't learn how to calculate the area of polygons yet.

OpenStudy (anonymous):

but, just work your way back with the equation to find the length of one side of the hexagon then multiply that by 4 then re-calculate the area

OpenStudy (anonymous):

Do you have the formula?

OpenStudy (pagen13):

no... i am really bad at math

OpenStudy (anonymous):

One sec, I'm working on it

OpenStudy (anonymous):

I found it, you see that because these figures have to be similar (they are both regular hexagons), there exists a ratio of their areas consistent with their ratio of side lengths 1:4. An area unit is just a length unit squared (A = k l^2), so the ratio between the areas is 1^2 : 4^2 or 1:32.

OpenStudy (anonymous):

so, now just use cross multiplication to find the area!

OpenStudy (anonymous):

\[\frac{ 38 }{ 1 } \frac{ x }{ 32 }\] So, x = 32*38/1

OpenStudy (anonymous):

wait sorry

OpenStudy (anonymous):

the answer is d.

OpenStudy (pagen13):

thank you

OpenStudy (anonymous):

I made an error, the answer is still d but the ration of the area is 1:16 not 1:32

OpenStudy (anonymous):

And NP! Glad I could help

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