What are a) the ratio of the perimeters and b) the ratio of the areas of the larger figure to the smaller figure? a. 5/2 and 25/4 b. 5/2 and 7/4 c. 7/2 and 25/4 d. 7/2 and 7/4
@sammixboo @Cicilybailey14 can you help?
Question, is the number assigned to the shapes already the perimeter?
or is it the area?
@Pagen13 Answer please
the perimeter i think?
ok well the for the first one, it's as easy as dividing the bigger one by the smaller one then simplifying
so, 30/12 15/6 5/2
Okay so the first one is 5/2 how do i find the second part?
well, I would go with logic.
We already eliminated 2 of those answers
a?
and we know tat the second shape is aprox twice the size as the smaller one
right. So the answer is A
I think so
Can you help with a couple more?
sure
are you a VLACS or FLVS student?
The area of a regular hexagon is 38cm2. What is the area of the regular hexagon with sides four times as long? a. 152cm2 b. 228cm2 c. 304cm2 d. 608cm2 And no i am not
oh ok Let's see... we want the area?
yes
Sorry, I didn't learn how to calculate the area of polygons yet.
but, just work your way back with the equation to find the length of one side of the hexagon then multiply that by 4 then re-calculate the area
Do you have the formula?
no... i am really bad at math
One sec, I'm working on it
I found it, you see that because these figures have to be similar (they are both regular hexagons), there exists a ratio of their areas consistent with their ratio of side lengths 1:4. An area unit is just a length unit squared (A = k l^2), so the ratio between the areas is 1^2 : 4^2 or 1:32.
so, now just use cross multiplication to find the area!
\[\frac{ 38 }{ 1 } \frac{ x }{ 32 }\] So, x = 32*38/1
wait sorry
the answer is d.
thank you
I made an error, the answer is still d but the ration of the area is 1:16 not 1:32
And NP! Glad I could help
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