Question

Help with an Integral.

Answer 1

shoot

Answer 2

\[\int\limits \frac{ x-1 }{ x^2-4x+5}dx\]

Answer 3

I factored the bottom and got \[(x-2)^2+1\] not sure on next step

Answer 4

\[2x-4\]

Answer 5

dang... misread it

Answer 6

You helped me though I think I can write the top as \[(x-2)+1\]

Answer 7

ok...

Answer 8

so I now have \[\int\limits \frac{ (x-2)+1 }{ (x-2)^2+1 }\].
I think i can solve now

Answer 9

Thank you