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OpenStudy (anonymous):
What is the distance between points (8, –4) and (8, –11) on a coordinate plane?
units
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OpenStudy (anonymous):
plz help
OpenStudy (anonymous):
medal and fan
OpenStudy (thehollywoodstud):
well do you know the equation to solve this?
OpenStudy (thehollywoodstud):
you have to make a triangle out of the two points like so
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OpenStudy (jdoe0001):
\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ 8}}\quad ,&{\color{blue}{ -4}})\quad
% (c,d)
&({\color{red}{ 8}}\quad ,&{\color{blue}{ -11}})
\end{array}\qquad
% distance value
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)
OpenStudy (thehollywoodstud):
8-8 is what ?
OpenStudy (anonymous):
0
OpenStudy (thehollywoodstud):
so 0+-11--4?
OpenStudy (solomonzelman):
| -4-(-11) |
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OpenStudy (thehollywoodstud):
well you cant have two negatives so thats a positive
OpenStudy (thehollywoodstud):
so -11+4
OpenStudy (thehollywoodstud):
is what?
OpenStudy (thehollywoodstud):
which is 7
OpenStudy (jdoe0001):
anyhow, the fellow kinda dashed
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OpenStudy (thehollywoodstud):
so then 7+0=7
do the d=sqrt(7)
OpenStudy (thehollywoodstud):
my bad then you have to do\[7^2=49 and the 4^2= 16 then add the two =65\]
OpenStudy (thehollywoodstud):
which is 8.06
OpenStudy (thehollywoodstud):
is that and answer choice ?@njrevine
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