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For harmonic motion equation D=9cos((pi/2)t) the frequency would be (pi/2) / 2pi
Frequency = cycles/unit of time
So its (pi/2)/2pi?
Yes but that can simplify.
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How?
(Pi/2)/(2pi) is the same as (pi/2) * (1/2pi) which equals?
2.4674011002723397
\[\frac{ \frac{\pi}{2} }{ 2\pi } = \frac{ \pi }{ 2 } * \frac{ 1 }{ 2\pi }\] because the reciprocal of 2pi is 1/2pi so the answer is \[\frac{ \Pi }{ 4\pi }\]
pi cancels and you are left with?
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4
No, you would have 1/4 wouldn't you?
oh yeah
So it's saying 1 cycle per 4 units of time and that's your frequency.
ok, thank you
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