Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (ohohaye):

Help please

OpenStudy (ohohaye):

OpenStudy (anonymous):

For harmonic motion equation D=9cos((pi/2)t) the frequency would be (pi/2) / 2pi

OpenStudy (anonymous):

Frequency = cycles/unit of time

OpenStudy (ohohaye):

So its (pi/2)/2pi?

OpenStudy (anonymous):

Yes but that can simplify.

OpenStudy (ohohaye):

How?

OpenStudy (anonymous):

(Pi/2)/(2pi) is the same as (pi/2) * (1/2pi) which equals?

OpenStudy (ohohaye):

2.4674011002723397

OpenStudy (anonymous):

\[\frac{ \frac{\pi}{2} }{ 2\pi } = \frac{ \pi }{ 2 } * \frac{ 1 }{ 2\pi }\] because the reciprocal of 2pi is 1/2pi so the answer is \[\frac{ \Pi }{ 4\pi }\]

OpenStudy (anonymous):

pi cancels and you are left with?

OpenStudy (ohohaye):

4

OpenStudy (anonymous):

No, you would have 1/4 wouldn't you?

OpenStudy (ohohaye):

oh yeah

OpenStudy (anonymous):

So it's saying 1 cycle per 4 units of time and that's your frequency.

OpenStudy (ohohaye):

ok, thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!