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Mathematics 15 Online
OpenStudy (lexi724):

If you are given an exponential graph and told to write and equation for it, how would you do that ex. is #7 and #8 on this link http://cdn.kutasoftware.com/Worksheets/Alg2/Graphing%20Exponential%20Functions.pdf

OpenStudy (empty):

since its exponential you know it has this form \[y=a^x+b\] so a trick you can use if you understand that anything to the zero power =1 \[a^0=1\] then at the center of your graph you can find out what b is. then plug it x=1 and you can find a similarly

OpenStudy (lexi724):

okay so # 7 is \[y=4^x+1\] how would we find that

OpenStudy (empty):

so we start with \[y=a^x+b\] plug in the point on your graph (0,2)

OpenStudy (lexi724):

so \[y=0^2+2\] would this be correct @iGreen @Empty @rational @Jamierox4ev3r

OpenStudy (lexi724):

okay so I guess no ones helping with this one.

OpenStudy (rational):

hey it seems you have answers below those graphs ?

OpenStudy (lexi724):

im not looking for answers tough i wanna know how to do it @rational

OpenStudy (rational):

\[y = a^x+b\] plug in the point on your graph (x,y) = (0,2)

OpenStudy (lexi724):

i did that above

OpenStudy (lexi724):

i was askign if i was right what to do from there

OpenStudy (rational):

that didnt look all that correct, try again

OpenStudy (rational):

you need to plugin x = 0 and y = 2

OpenStudy (rational):

the idea is to solve a,b values using the points on graph

OpenStudy (lexi724):

\[2=0^2+b\]

OpenStudy (rational):

why are you replacing a by 0 ?

OpenStudy (rational):

\[y = a^x + b\] plugging in \((x,y) = (0, 2)\) you get \[2 = a^0 + b\] right ?

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