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OpenStudy (itsyacoolgrl):
with what? :)
OpenStudy (anonymous):
OpenStudy (anonymous):
@Itsyacoolgrl
OpenStudy (itsyacoolgrl):
@amistre64
OpenStudy (anonymous):
HELP bwaaahhahaaaaaa
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OpenStudy (phi):
first, direct variation means we have an equation
y = k x
where k is a constant.
however, "quadratic variation" is a fancy way to say "use x^2" instead of x
in other words, direction variation with the square of x:
y = k x^2
the next step is to find k.
to do that, use one of the (x,y) pairs in the table.
can you do that ?
OpenStudy (phi):
can you pick an (x,y) pair from the table ?
OpenStudy (anonymous):
2 24
OpenStudy (anonymous):
is the answer 6
OpenStudy (anonymous):
@phi
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OpenStudy (anonymous):
@amistre64
OpenStudy (phi):
with 2,24
that is, x=2 and y=24
you use those numbers instead of "x" and "y" in
y = k x^2
in other words, erase "y" and put 24 in its place
do the same for x: erase the x, and put in 2 in its place
what do you get ?
OpenStudy (anonymous):
6
OpenStudy (phi):
you get
24= k 2^2
2^2 means 2*2 , which is 4
24 = k*4
to find k , divide both sides by 4
OpenStudy (anonymous):
so its 6
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OpenStudy (anonymous):
@phi
OpenStudy (phi):
k is 6
you can test it. the equation is
y = 6 x^2
if this is correct, then if we "put in" x, we should "get out" the correct y
OpenStudy (phi):
For example, for x=3, the equation says
y = 6*3^2 or
y= 6*3*3
and that simplifies to
y= 54
which matches the table. Looks good.