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Mathematics 13 Online
OpenStudy (anonymous):

help please

OpenStudy (itsyacoolgrl):

with what? :)

OpenStudy (anonymous):

OpenStudy (anonymous):

@Itsyacoolgrl

OpenStudy (itsyacoolgrl):

@amistre64

OpenStudy (anonymous):

HELP bwaaahhahaaaaaa

OpenStudy (phi):

first, direct variation means we have an equation y = k x where k is a constant. however, "quadratic variation" is a fancy way to say "use x^2" instead of x in other words, direction variation with the square of x: y = k x^2 the next step is to find k. to do that, use one of the (x,y) pairs in the table. can you do that ?

OpenStudy (phi):

can you pick an (x,y) pair from the table ?

OpenStudy (anonymous):

2 24

OpenStudy (anonymous):

is the answer 6

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

@amistre64

OpenStudy (phi):

with 2,24 that is, x=2 and y=24 you use those numbers instead of "x" and "y" in y = k x^2 in other words, erase "y" and put 24 in its place do the same for x: erase the x, and put in 2 in its place what do you get ?

OpenStudy (anonymous):

6

OpenStudy (phi):

you get 24= k 2^2 2^2 means 2*2 , which is 4 24 = k*4 to find k , divide both sides by 4

OpenStudy (anonymous):

so its 6

OpenStudy (anonymous):

@phi

OpenStudy (phi):

k is 6 you can test it. the equation is y = 6 x^2 if this is correct, then if we "put in" x, we should "get out" the correct y

OpenStudy (phi):

For example, for x=3, the equation says y = 6*3^2 or y= 6*3*3 and that simplifies to y= 54 which matches the table. Looks good.

OpenStudy (anonymous):

so its 6

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