Adena has a number cube whose sides are labeled 1 through 6. She rolls the number cube three times.
What is the probability that Adena will roll 2, then 3, and then 4?
IT HAS TO BE A FRACTION!!!! I WILL GIVE MEDAL AND FAN!
Still Need Help?
Join the QuestionCove community and study together with friends!
On the first roll, the probability of rolling a 2 is 1/6.
On the second roll the probability of rolling a 3 is also 1/6, and the probability of rolling a 4 on the third roll is, you guessed it, 1/6.
Therefore the required probability is given by:
\[\large \frac{1}{6}\times\frac{1}{6}\times\frac{1}{6}=you\ can\ calculate\]
OpenStudy (anonymous):
okay, i will tel u what i get in a sec
OpenStudy (anonymous):
okay, i got 1/216
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (kropot72):
You are correct.
OpenStudy (anonymous):
is that the answer?
OpenStudy (anonymous):
wow, i should have known :P
OpenStudy (kropot72):
Sure is!
OpenStudy (anonymous):
thx
Still Need Help?
Join the QuestionCove community and study together with friends!