Question

Below are the data collected from two random samples of 500 American adults on the number of hours they spend doing leisure and sports activities per day (rounded to the nearest hour):

Dan concludes that adults spend a mean of 3 hours each day doing leisure and sports activities. Bret thinks the mean is 4 hours. Who is correct—Dan or Bret? Explain your answer in two or three sentences.

Answer 1

@Michele_Laino

Answer 2

ok! Then we have to find in which intervals those means are. Namely I'm thinking about the distributions of each data

Answer 3

we have to draw an histogram for each distribution

Answer 4

so its 3 hours?

Answer 5

Mean for sample A:
$$\large { \frac{1*70 + 2*90 + 3*135+4*140 + 5*65}{70 + 90 + 135 + 140 + 65} }$$

Mean for sample B : $$ \large { \frac{1*80 + 2*80 + 3*130+4*135 + 5*75}{80 + 80 + 130 + 135 + 75} } $$

Answer 6

so sample A is 3.08 and sample B is.... i cant figure tht one out

Answer 7

u got 3.09 for B?

Answer 8

yes.
and the overall sample mean is the average of the two sample means

Answer 9

how do u find tht

Answer 10

$$ \Large \frac{3.08 + 3.09 }{ 2 } $$

Answer 11

3.085

Answer 12

yes

Answer 13

So what is your conclusion

Answer 14

The mean for sample A is 3.08, the mean for sample B is 3.09 and the overall sample mean is 3.085. So that's 3 hours which means Dan is correct.