Question

Given b=2 and h = 8, what is the equation of the graph if the parent function is y = /- positive x?

Answer 1

The /- is meant to represent square root, or basically it should look like this\[\sqrt{x}\]

Answer 2

And the possible answers are

a: y = \[\sqrt{2x+16}\]
B: y = \[\sqrt{2x-16}\]
C: y = \[\sqrt{2x}+16 \]
D: y = \[\sqrt{2x} - 16 \]

Answer 3

I don't know what b represents in this case. We usually use the letter a for amplitude but I guess that's not what the b is for in this case.
What does your standard form look like?\[\Large\rm y=\sqrt{b(x-h)}+k\]\[\Large\rm y=\sqrt{bx-h}+k\]One of those maybe?

Answer 4

Yah I guess it's that first one that I posted,
that's the only one which leads to a possible answer.

Remember that h represents a `horizontal shift`,
so that one needs to get stuck under the root with the x.

Answer 5

B is 2.

Answer 6

Unless you meant the answer of B.

Answer 7

\[\Large\rm y=\sqrt{b(x-h)}\]\[\Large\rm y=\sqrt{2(x-8)}\]B is 2?

Answer 8

B = 2 in terms of the variable.

Answer 9

? 0_o

Answer 10

Wait a minute...So technically it would be 2x+16, so that would mean A?

Answer 11

i have seen this before
this is not math
this is some system or math teacher made up math

Answer 12

oh b=2,
not B=2. Yah that's why I was getting confused by what you were saying :c heh

Answer 13

Whoops. I should have been more specific.

Answer 14

Yah it seems like this relates to some specific system that a teacher didn't tell the rest of us about :3 lol

Answer 15

A lil tricky to figure out

Answer 16

what is \(b\)? what is \(h\)? who knows
there is nothing here remotely in the realm of mathematics
there is no standard notation that says \(h\) is something and \(b\) is something, it it utter nonsense
refuse to do it

Answer 17

even the concept of "parent function" is silly

Answer 18

Aren't those variables? And b is equal to 2 and h is equal to 8.

Answer 19

yeah but what do they represent?

Answer 20

Nahhh don't listen to that grump ^
We can sort of read into what the teacher probably meant for this problem lol.

You want to `subtract` your h value.
So we're looking for something that looks like this probably:\[\Large\rm y=\sqrt{b(x-h)}\]

Answer 21

ooh i wouldn't bet on it !!

Answer 22

If we plug in our 2 and our 8,\[\Large\rm y=\sqrt{2(x-8)}\]Does that look like any of your options? Can we do something to match it up? :)

Answer 23

could be \(b(f(x)+h\) or \(f(bx+h)\) o r\(f(b(x+h))\) or \(f(bx-h)\)

Answer 24

I'm pretty sure that we could multiply 2 into x and -8.

Answer 25

Which would mean 2x - 16

Answer 26

ya that's probably what teach was looking for! :)
So option B, ya?

Answer 27

B? Yeah.

Answer 28

Regarding that other guy who was here, is that normal of him?

Answer 29

Yes. He gets grumpy over teachers mistakes and unconventional teaching methods :) lol
He's a silly guy.

Answer 30

Okay, I guess the "if you don't have anything constructive to say then leave" response will be unnecessary.

Answer 31

Ehh he's just gotta get it out of his system sometimes XD I dunno, its weird
haha

Answer 32

Alright. I'll let it alone then. Thanks.