Check plz. Remi has two cone-shaped containers with the same diameter. He will place the smaller container inside the larger one. Before he does this, he wants to fill the larger container with water so that it will be completely full but won’t spill when he places the smaller container inside. The diameter of both containers is 12 cm. The height of the smaller container is 6 cm, and the height of the larger container is 18 cm. What volume of water must Remi put in the large container? Use 3.14 to approximate pi and express your final answer in hundredths. ___cm3 I got 718.01 cm3
volume large - volume small right?
Huh?
its a simple idea ... what about it is confusing?
It was a little but was I right?
dunno, im trying to formulate a solution. would you agree that the required volume is just the volume of the large cone; minus the volume of the small cone?
Idek I just wanted to know if I was right
i wont know if your right until we know how to approach a solution, are we just guessing at stuff?
how did you come up with your own solution?
area of base for both are equal area of base=area of circle=pi times r^2 radius=diameter/2 diameter=14 radius=14/2 radius=7 pi times 7^2 pi times 49 3.14 times 49=153.86 smaller so 1/3 times 153.86 times 3=smaller cone=153.86 cm^3 larger so 1/3 times 153.86 times 17=871.873 subtract smaller from larger 871.873-153.86=718.013 cm^3 the volume of water needed is 718.01 cm^3
good, we were on the right track, let me dbl chk your results
Just out of curiosity how old r u?
1/3 pi r^2 H - 1/3 pi r^2 h , since they have the same radius we can factor most of this out 1/3 pi r^2 (18 - 6) is the volume needed you have an error: diam = 12, r=6, not 7 36/3 pi (18 - 6) 12(12) pi = 144pi, use 3.14 is instructed to get 144(3.14) I am about 25 years older than my kids :)
452.16 and oh lol just asking
now we know if your original amount is correct or not ;) good luck
THXc:
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