Question

Identify the GCF of 9a^4b^4-27a^3b^3+18a^3b^2
A.) 9a^3b^3
B.) 9a^3b^2<----
C.) 3a^2b^3
D.) 3a^3b^2

Answer 1

@Godlovesme @UnkleRhaukus @wolf1728

Answer 2

I think u r correct :) but tag other peeps to make sure

Answer 3

okay thank you(:

Answer 4

Anytime : )

Answer 5

\[9a^4b^4-27a^3b^3+18a^3b^2\\
=9a^3b^2(ab^2)-9a^3b^2(3b)+9a^3b^2(2)\\
=9a^3b^2(ab^2-3b+2)\] yep

Answer 6

Thank you !!(:

Answer 7

gcd is greatest common divisor that means greatest value which can divide all
first talk about numbers in your prblm that is 9,18 27
9=3*3
18=2*3*3
27=3*3*3

in above you can see max coommon value in all is
3*3 that is 9
now talk about alphabets 9a^4b^4-27a^3b^3+18a^3b^2
first one=9*a*a*a*a*b*b*b*b
second=9*3*a*a*a*b*b*b
third=9*2*a*a*a*b*b
max common term from all is 9*a^3*b^2

got it?

Answer 8

yes i do thank you!!(: