Question

tan(e^2x)find dy/dx?

Answer 1

Just use chain rule here: \([f(g(x))]' = f'(g(x))\cdot g'(x)\)

In your case, we have \(f(x) = \tan(x)\) and \(g(x) = e^{2x}\)

Answer 2

@supikaran

Answer 3

yeap, chain-rule it

Answer 4

\(\bf \cfrac{d}{dx}[{\color{brown}{ tan({\color{blue}{ e^{2x}}})}}]\implies \cfrac{d}{dx}{\color{brown}{ tan(e^{2x} )}}\cdot \cfrac{d}{dx}[{\color{blue}{ e^{2x} }}]\)

Answer 5

a.sec^2(e^2x)
b.2e^2xsec2(x)
c.2e^2xsec^2(e^2x)
d.2tan(e^2x)sec^2(e^2x)
e2e^2xtan(e^2x)+sec^2(e^2x)
whih one is the answer