Question

tan(e^2x)find dy/dx?
a.sec^2(e^2x)
b.2e^2xsec2(x)
c.2e^2xsec^2(e^2x)
d.2tan(e^2x)sec^2(e^2x)
e2e^2xtan(e^2x)+sec^2(e^2x)
whih one is the answer

Answer 1

You're gonna have to use the chain rule, so first take the derivative of tan
\(\Large \frac{dy}{dx} tanx=\sec x^2 \)

Now the derivative of \(e^{2x} \)

In all you should end up with: \(\Large \sec^2(e^{2x}) *2 e^{2x} \)