Question

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Answer 1

@lυἶცἶ0210

Answer 2

.....

Answer 3

Find the center, vertices, and foci of the ellipse with equation \(2x^2 + 8y^2 = 16\)
options: http://prntscr.com/6snz9q

Answer 4

You know to get to the standard equation right?

Answer 5

\(\dfrac{(x-h)^2}{a^2} + \dfrac{(y-k)^2}{b^2} = 1\)

Answer 6

Divide both sides to get it equal to 1:

\(\Large \frac{ 2x^2}{16}+\frac{8y^2}{16} =1 \)

Simplify:

\(\Large \frac{x^2}{8} +\frac{y^2}{2} =1\)

Answer 7

Now that we got it there we can look for the vertices and everything else that makes an ellipse an ellipse

Answer 8

This isn't shifted at all, so you can guess the center right?

Answer 9

0, 0

Answer 10

Right, now the vertices depend on the major axis, do you know which axis is the major one?

Answer 11

Horizontal?

Answer 12

If horizontal means x, then yes xD

Answer 13

Now we need to find those vertices, a, but we have a^2, so taking the square root: \(\large \pm 2\sqrt{2} \)

Answer 14

And remembering where they're placed \(\Large (\color{red}{x}, ~y ) \)

Answer 15

D?

Answer 16

I would love to believe so :P

Answer 17

:)

Answer 18

You can find the foci if you want, but there's only one option as to what it could be ~

Answer 19

lol @jagr2713 :P