last one. Using the ratio of perfect squares method, what is square root of 128 rounded to the nearest hundredth?
Just use calculator, What do you get?
11.31
thats it?
Yep.
i get it nowwwww!!!! Yaaay
its reaaaally easy
Just so you know, this is not how you use "ratio of perfect squares method." But we are not really familiar with it, so yeah.
oh. crap. i failed my practice session. i got a forty%
just finish math homework and get over it haha
you got right on last two questions though?
i missed all three
Really? So 11.31 is not right?
it was 11.30 suuuuuper close
This is so wrong...
my thing is?
http://www.wolframalpha.com/input/?i=sqrt%28128%29 Must be because of some round up error.
maybe we really need to know this method, sorry for getting you wrong on questions.
its alright! thanks for trying to help me
@geerky42 I have never heard of that method either and I can not find this method on google.
Perhaps the op can tell us the method.
using the method is probably how they got 11.30 however the method is performed
I think @triciaal is familiar with it, she just did her work on OP's previous question. We would like to know what this method is.
Currently idling lol...
\[11=\sqrt{121}<\sqrt{128}<\sqrt{144}=12\] I know this
idk man. i just transferred from half a year of pre-al to Algebra senester 2
Given the equations 9x+34y=6 and 2x+12y=9, by what factor would you multiply the second equation to eliminate y and solve the system through linear combinations? −43 −34 −32 −72 does anyone get this?
semester*
dude. make your own thread
Please don't post your question on other user's question. @Nieke
11+12=23 128-121=7 144-128=16 so what is 16/23=.6957 and 7/23=.30435 so somehow I think we suppose (somehow choose) to say 11+.30435 11.30435 which rounded to the nearest hundredth is 11.30
oh by the way 16/23=.6957 and 7/23=.30435 we approximations
I think the method being talked about in this khan video may be the method
Could be it. It fits well.
did you figure it out? because im not really understanding this khan video
Join our real-time social learning platform and learn together with your friends!