Question

Simplify/ Condense this logarithm. WILL MEDAL!

Answer 1

\[\log_{c}(a)+\log_{c}(b)=\log_{c}(a \times b)\]
\[\log_{c}(a)-\log_{c}(b)=\log_{c}(\frac{ a }{ b })\]
\[alog_{c}(b)= \log_c{}(b^{a})\]

Answer 2

use these rules of logarithms to answer your question

Answer 3

I got it!!!

Answer 4

also

if
\[\log_{c}(a)=b\]
then
\[c^{b}=a\]

Answer 5

gratz

Answer 6

\[\log_4 2 ^8 +\log_4(r-3)^1/6 -\log_4 \sqrt{r}\]

Answer 7

The thing is, Idk how to continue from here ! Lol

Answer 8

you can simplify your 2^3 to be 8
so I would simplify that first

Answer 9

then you are adding the first two logarithms, so you would use the log rule where you multiply them

log(a)+log(b)=log(a x b)

Answer 10

then you would subtract the next logarithm from your answer so you use the division rule

log(a)-log(b)=log(a/b)

Answer 11

I mean you could actually get an actual value from the first logarithm

\[\log_{4}(8)=3/2\]

Answer 12

but i don't know if you wanna keep it as one whole logarithm

Answer 13

if you have anymore questions let me know

Answer 14

Im still working on it! Lol

Answer 15

Got it thank you!!!!

Answer 16

glad I could help!