@matt101 Last Two Electricity Problems
How do you think you could solve #4?
You got it!
How would I rearrange the equation, so I am finding the magnitude?
Yes, you are finding the magnitude of one of the charges
\[65={(9 \times 10^9) \times (6 \times 10^{-6}) \times q_2 \over 0.05^2}\] How would you isolate q2?
Yup!
@matt101 Is it 108.33 repeating?
Check your math - that's an awfully big charge!
That's it!
Yup
Okay! Thank you so much! How would I do the three parts to number 5?
It's a question of adding forces to come up with the net force. Just use Coulomb's Law as usual!
Really? Wow, nearly all of these used his law!
Would the origin be 0 for A?
@matt101
Yes
Well keep in mind you have 3 charges in this situation. Each particle will experience 2 forces - one as a result of one of the other particles, and one as a result of the OTHER other particle. This means you'll need to add 2 forces to get the net force on each particle. Each force you can find using Coulomb's Law. Just be careful with the directions of the forces!
Oh gosh. This is confusing already. I get what you're saying but how do I know which numbers to add?
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