In Pensacola in June, high tide was at noon. The water level at high tide was 12 feet and 2 feet at low tide. Assuming the next high tide is exactly 12 hours later and that the height of the water can be modeled by a cosine curve, find an equation for water level in June for Pensacola as a function of time (t).
@dtan5457
can any one please help me solve this step by step?
cant you create a chart to find d=rt?
what ? im sorry i dont understand :/
umm hold on. let me make sure Im giving you the right information
ok
Ive not worked with cos functions. im sorry Im not going to be any help here.
@amistre64 might be able to help
ok alright thanks
@jim_thompson5910
@SithsAndGiggles
@dtan5457
can one of you guys walk me through this?
oh ive tried helping before :) we need to determine amplitude, and period to start things off with
how do we define amplitude?
amplitude is the highest point on the y axis which is the distance right? it has to be a positive number?
amplitude is half the distance between the lowest and highest values for the Y axis. (high - low)/2 = amplitude from the stated problem what is the amplitude?
these are the parts we want to determine. midline period vv vv y = M + A cos( P t) ^^ amp
midline is the average of low and high M = (low+high)/2 amplitude is half the height, and M is in the center, so adding M+A gives us the high point A = high - M period is a measure of how long it takes to repeat itself, since cos(u) has a normal period of 2pi, and we know that it takes 12 hours to go to low tide, and itll presumably take another 12 hours to get back to high tide (general assumptions); then we t=24 .. u = Pt; when t=24, u=2pi P(24) = 2pi must be satisfied.
i know that the amplitude is 5
@amistre64
good, and the midline?
A = high - M we know A and high, find M or another way, average high and low
what is the midline again?
im not going to make a long drawn out posting of repeating myself over and over when what ive already typed is sufficient. scroll up and read. if its unclear, then ask questions about what ive already stated.
ohhhh is it 7 ?
@amistre64
now your going to make me ... 12 + 2 14 ... yeah 7s fine :)
so far we have: y = 7 + 5cos(u) just have to determine u = Pt for the period ...
so, 24=2pi do i simplify this? or factorize it ?
24 P = 2pi, its a basic algebraic process to find P ...
do i divide by 24 at both sides to isolate the variable?
correct
so P= 2pi/24
or simply P = pi/12 now put the equation together y = M + A cos(Pt)
do i simplify this?
but pi over twelve isnt any of my options
@amistre64 isnt there a way ti simplify it more?
it*
i dont know what your options are
here they are
t it be c?
it takes 12 hours to go from high to low, so it would take 24 hours to go from high to high; P 24 = 2pi when P = pi/12
Assuming the next high tide is exactly 12 hours later i misread the info ..... pi/6 is fine
C is the most likely option since it fits the Midline and Amp as determined .... and pi/6 is good is correct when we do the actual problem instead of making things up lol
XD thanks a lot for your help :-)
your welcome :)
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