Can someone tell me if I'm right?
I think it's C Which graph correctly solves the system of equations below? y = – x^2 + 1 y = x^2 – 4 A. https://lss.brainhoney.com/Resource/22181743,AD2,0,C,3,0/Assets/72257_53b5b170/0608_g8_q3a.jpg B. https://lss.brainhoney.com/Resource/22181743,AD2,0,C,3,0/Assets/72257_53b5b170/0608_g8_q3b.jpg C. https://lss.brainhoney.com/Resource/22181743,AD2,0,C,3,0/Assets/72257_53b5b170/0608_g8_q3c.jpg D. https://lss.brainhoney.com/Resource/22181743,AD2,0,C,3,0/Assets/72257_53b5b170/0608_g8_q3d.jpg
@texaschic101 Am I right?
@dtan5457
The original formula for a parabola is \[y=ax ^{2}+bx+c\], where a is the value attached to the x^2 variable. Apart from that, when a>0, the parabola will be U-shaped and when a<0, it will be cap-shaped. Having this in mind, the first equation, where the a is -1, then the parabola has to be cap-shaped. The second, where a is +1, shall be U-shaped. b is the value attached to the x variable and c is the y-intercept value (not attached to any variable) The first equation has a value of +1 as the y intercept and the second has the value of -4.
Ok so am I right? It's C?
B and C are quite similar, therefore it is important to find the roots. especially for the second equation, because in B there are no roots and in C there are.
\[x ^{2}-4=0\] \[x ^{2}=4\] \[x=-2orx=2\] These are the roots, then you were correct. C.
@vera_ewing
thanks @Hoslos
My pleasure.
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