Ask your own question, for FREE!
Mathematics 16 Online
rvc (rvc):

the number of ways of selecting 15 teams from 15men and 15 women, such that each team consists of a man and a women is:

OpenStudy (anonymous):

first of all check how many members will be in each team

OpenStudy (anonymous):

each team will have 2 members .

rvc (rvc):

one team two members

OpenStudy (anonymous):

while selecting first team u will have 15 men and 15 women .

rvc (rvc):

so 1st team any one from 15 men and women

OpenStudy (anonymous):

when u will select the second team u will have 13 members .and so on

rvc (rvc):

15*15+14*14+13*13+.......+1*1 right?

rvc (rvc):

1240 is the ans ,right?

rvc (rvc):

nope thats wrong i suppose 1240 is correct i think

rvc (rvc):

@Haseeb96 pls check

OpenStudy (perl):

yes that makes sense 1240

OpenStudy (haseeb96):

sorry i was wrong the correct answer is 1280 .

OpenStudy (haseeb96):

*1240

OpenStudy (haseeb96):

i m 100% sure it is correct

OpenStudy (perl):

First start with the full sample space. S = { m1,m2,m3,m4, m5, m6,m7,m8,m9, m10, m11,m12,m13,m14, m15, w1,w2,w3,w4, w5, w6,w7,w8,w9,w10, w11,w12,w13,w14, w15 } For the first team you have 15 men to choose from and 15 women to choose from, so there is 15*15 ways to produce first team. Now you have 14 men and 14 women left to choose from for next team. There are 14*14 ways to produce second team. keep doing this until you have 1 man and 1 woman left . that makes 1*1 team

rvc (rvc):

okay thank you :)

OpenStudy (haseeb96):

@rvc did u get it ?

rvc (rvc):

yes thank you !

OpenStudy (haseeb96):

this kind of question comes in entry test.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!