Question

Assuming x ≠ 0 and y ≠ 0, what is the quotient of ...

Answer 1

\[24x^6y^2 + 16x^4y^3 + 8x^2y^4 \over 4x^2y\]

Answer 2

@misty1212

Answer 3

separate the three fractions

Answer 4

How? Can you walk me through it please? :)

Answer 5

\[\frac{24 x^6y^2}{4x^2y}+\frac{16x^4y^3}{4x^2y}+\frac{8x^2y^4}{4x^2y}\]

Answer 6

now simplify wach fraction

Answer 7

24/4=?
x^6/x^2=? use quotient rule
y^2/y=?

Answer 8

Okay, gimme a sec to do this on paper. Please don't leave yet.

Answer 9

Would we have 6, x^4 and y?

Answer 10

yep

Answer 11

Okay. Do you know what to do from here?

Answer 12

\[\frac{24 x^6y^2}{4x^2y}+\frac{16x^4y^3}{4x^2y}+\frac{8x^2y^4}{4x^2y} \\ 6x^4y+\frac{16x^4y^3}{4x^2y}+\frac{8x^2y^4}{4x^2y} \]

Answer 13

you need to do the other two fractions

Answer 14

Also, I apologize for any delayed replies. My computer is having issues.

Answer 15

Okay. One minute.

Answer 16

Sorry I had something burning in the kitchen.

Answer 17

Would we have 4, x^2 and y^2?

Answer 18

For the second fraction

Answer 19

And for the third fraction would we have 2, x and y^3?

Answer 20

the third fraction is just a lil bit off

Answer 21

anything not equal to 0
where you have that anything divide by itself is 1

Answer 22

that is like example
5/5=1
6/6=1
-5/-5=1

x not 0
x/x=1

x^2/x^2=1

Answer 23

I thought that a variable always had ^1 but it was not seen. For example, instead of x^1 it would be x.

Answer 24

x^1 is x

Answer 25

x^0 is 1

Answer 26

Oh I understand now! Thank you! :)

Answer 27

np