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Mathematics 23 Online
OpenStudy (sagewilson):

find the Total Are for the Prism (L.A is (80 + 16 √13)

OpenStudy (sagewilson):

OpenStudy (sagewilson):

@TuringTest

OpenStudy (sagewilson):

@Nnesha

OpenStudy (sagewilson):

@campbell_st @jim_thompson5910

OpenStudy (tabdo1226):

please help

OpenStudy (rizags):

Total Area, you mean Surface Area Right?

OpenStudy (sagewilson):

Yes

OpenStudy (rizags):

SA = wh + lw + lh + ls, where w = width h = height l = length s = side

OpenStudy (rizags):

|dw:1428972059116:dw|

OpenStudy (campbell_st):

1st task is to find the missing side of the right triangle |dw:1428971855218:dw| then you can start to find the area of each face

OpenStudy (rizags):

that is for a right triangular prism, like yours

OpenStudy (rizags):

@campbell_st i dont think you need that missing side, because to find the area of the triangle, you dont need that side

OpenStudy (rizags):

oh but yes, you do to find the rectangle, sorry

OpenStudy (sagewilson):

would it be 4^2 + 6^2 = the Surface Area?

OpenStudy (sagewilson):

no wait, the answer is supposed to be ? + ? - ? √

OpenStudy (sagewilson):

@satellite73

OpenStudy (sagewilson):

@dan815

OpenStudy (anonymous):

No, you are using that just to find the length of the diagonal.

OpenStudy (anonymous):

\[ 4^2+6^2=(?)^2 \]

OpenStudy (sagewilson):

4^2 would be 16 and 6^2 would be 36 which would be 52. I'm not sure how to put that into a power of 2 form

OpenStudy (anonymous):

\[ \sqrt{52} = \sqrt{4 \cdot 13} = 2\sqrt{13} \]

OpenStudy (anonymous):

This is good enough for the problem.

OpenStudy (anonymous):

Now we can start calculating areas for the surfaces

OpenStudy (sagewilson):

Okay so how would I find the surface area?

OpenStudy (anonymous):

You want to number each face

OpenStudy (anonymous):

There are two triangle faces and 3 rectangular faces

OpenStudy (anonymous):

Solve the area for each one, and add them all up

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