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Mathematics 20 Online
OpenStudy (precal):

Does a limit exist at a vertical asymptote?

DivineSolar (divinesolar):

Well i really do not try to give out direct answers but maybe this can help? -> http://archives.math.utk.edu/visual.calculus/1/vertical.4/

OpenStudy (precal):

I am given a grap of a function where the vertical asymptote shows arrows going upward towards positive infinity. Does that mean the limit does not exist?

OpenStudy (precal):

I thought the limit did exist for this one, I wanted to say positive infinity for the limit.

DivineSolar (divinesolar):

Please hold on for a second.

DivineSolar (divinesolar):

I gave you that link to help as right now i do not do calculus :). So i tried to help you in a way ^-^. Sorry that i cannot help any further :(.

DivineSolar (divinesolar):

I am way behind you in grade levels man ^-^

OpenStudy (anonymous):

It depends on what you consider to be existence, and the type of asymptote.

OpenStudy (anonymous):

For example, I would say \[ \lim_{x\to 0}\frac{1}{x^2} = \infty \]To be an asymptote with a limit that exists.

OpenStudy (precal):

Basic Calculus level, nothing higher, High School Calculus and I am studying for the Ap Exam

OpenStudy (precal):

yes graph is a piecewise and does have that similarity in the graph of that particular function

OpenStudy (anonymous):

Limit exists if right and left hand limits are equal

OpenStudy (anonymous):

For an vertical asymptote, you know that at least one of the one sides limits exist.

OpenStudy (precal):

Both going upward towards positive infinity

OpenStudy (precal):

Maybe it is a typo in my key.

OpenStudy (precal):

thanks... I am going to double check my book for the exact definition but I believe it could just be a typo

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