Question

Can I please be helped I really dont get this problem ):) Medal and Fan! Which expression is equivalent to this in its lowest terms?

Answer 1

\[\sqrt{98x ^{8}y ^{5}z ^{40}}\]

Answer 2

what is half of 8?

Answer 3

4

Answer 4

so an \(x^4\) comes right out front
what is half of 40?

Answer 5

20

Answer 6

out comes a \(z^{20}\)
how many times does 2 go in to 5?

Answer 7

2 times

Answer 8

with a remainder of?

Answer 9

1

Answer 10

ok good, so out comes
\(y^2\) in stays \(y^1\) which is just \(y\)

Answer 11

so far we are at
\[x^4y^2z^{20}\sqrt{98y}\] now we take care of the \(98\)

Answer 12

\[98=49\times 2\] so
\[\sqrt{98}=\sqrt{49\times 2}=\sqrt{49}\sqrt{2}=7\sqrt2\]

Answer 13

in other words out comes a 7, in stays a 2

Answer 14

final answer
\[7x^4y^2z^{20}\sqrt{2y}\] not too hard

Answer 15

Thank you :) I did learn *thumbs up* !