Find the angle between the given vectors to the nearest tenth of a degree. u = , v = 0.9° -9.1° 1.8° 11.8°

Question

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> 0.9° -9.1° 1.8° 11.8°

anonymous · Answer

i think its 0.9 but lol just wanna clarify

misty1212 · Answer

HI!!

misty1212 · Answer

ok that was wrong sorry

anonymous · Answer

so let me see im confused on how to set it up lol would you mind showing me! the steps and stuff :) @misty1212

anonymous · Answer

lol i figured i did something wrong lol

misty1212 · Answer

take the dot product, you get $32$ if i am not mistake

misty1212 · Answer

then divide by the norm of both vectors
you know how to find that?

anonymous · Answer

no lol

anonymous · Answer

not sure what the norm would be

misty1212 · Answer

$$||<-5,-4>|=\sqrt{5^2+4^2}$$ just like pythatoras

anonymous · Answer

mhm i see

misty1212 · Answer

so 
$$\frac{32}{\sqrt{41}\sqrt{25}}$$

misty1212 · Answer

then take the arc cosine

anonymous · Answer

mhm im watching

misty1212 · Answer

anonymous · Answer

so i put that in and i got really weird numbers lol

anonymous · Answer

0.0312398334 rad

anonymous · Answer

@misty1212 can you show me what it is please lol im confused

misty1212 · Answer

your calculator is in radian mode, but your answers are in degrees

misty1212 · Answer

either put your calculator in degree mode, or just click on the link i sent
the answer is there, both in degrees and in radians

anonymous · Answer

hmm i just dont know what the answer would be feel like im mixing all my numbers up lol

anonymous · Answer

1.7899106065º i converted the radians to degrees

anonymous · Answer

oh its 1.8!!! okay