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Mathematics 19 Online
OpenStudy (anonymous):

I need help figuring what the next question is asking me to find, any help would be really appreciated. Thanks (: Let g be the function defined by g(x)=xf(x). Find an equation for the line tangent to the graph of g at x=.

OpenStudy (anonymous):

x=?

OpenStudy (anonymous):

@satellite73 how do I figure out what g is if I am only given the graph of f(x)?

OpenStudy (anonymous):

you are missing what x is

OpenStudy (anonymous):

all i see is at \(x=.\)

OpenStudy (anonymous):

we need a number for x to do this

OpenStudy (anonymous):

look at your question it is missing the value of x we need that number, then we can do it

OpenStudy (anonymous):

@satellite73 x=2. sorry I thought I'd typed it.

OpenStudy (anonymous):

\[g'(x)=xf'(x)+f(x)\] by the chain rule so \[g'(2)=2f'(2)+f(2)\] you should find \(f(2)\) and \(f'(2)\) from the picture

OpenStudy (anonymous):

ok so I just basically have to use the chain rule in order to find what my g equals, correct? and thank you @satellite73 also does this apply every time or just in some cases?

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