Question

How to find the vertex, focus, and directrix of the parabola with this equation:
(x-5)+(y+4)^2=0

Answer 1

is that vertical or horizontal ?? do you know ?

Answer 2

umm i don't know... horizontal?

Answer 3

if x square then = vertical
and if y square = then it's horizontal

Answer 4

so yes it's horizontal

Answer 5

so for this equation, since (y+4)^2 this equation is horizontal

Answer 6

\[\large\rm (y-k)^2 = 4p(x-h)\]
standard form equation of parabola for horizontal

Answer 7

yep that is right :)

Answer 8

do I bring the (x-5) to the other side of the equation? to get (7+4)^2 by it self?

Answer 9

vertex is same as center

Answer 10

7 ???

Answer 11

opps i meant Y

Answer 12

yes right

Answer 13

\[(y+4)^2 = -(x-5) ??\]

Answer 14

yes that's right do you know what is 4p there ??

Answer 15

would it be 4(-0.25)?

Answer 16

nope look at the equation
4p = ?